Our top 5% students will be awarded a special scholarship to Lido.

Ml aggarwal solutions

CHAPTERS

**A rectangular pit 1.4 m long, 90 cm broad, and 70 cm deep was dug and 1000 bricks of base 21 cm by 10.5 cm were made from the earth dugout. Find the height of each brick.**

Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm

The volume of rectangular pit = l × b × h

= (140 × 90 × 70) cm^{3}

= 882000 cm^{3}

Volume of brick = 21 × 10.5 × h

Now,

Number of bricks = Volume of pit/ Volume of brick

1000 = 882000/ (21 × 10.5 × h)

h = 882000/ (21 × 10.5 × 1000)

= 4 cm

Thus, the height of each brick is 4 cm.

Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm

The volume of rectangular pit = l × b × h

= (140 × 90 × 70) cm^{3}

= 882000 cm^{3}

Volume of brick = 21 × 10.5 × h

Now,

Number of bricks = Volume of pit/ Volume of brick

1000 = 882000/ (21 × 10.5 × h)

h = 882000/ (21 × 10.5 × 1000)

= 4 cm

Thus, the height of each brick is 4 cm.

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2021 © Quality Tutorials Pvt Ltd All rights reserved